157=5+3x+2x^2

Solution for 157=5+3x+2x^2 equation:

157=5+3x+2x^2

We move all terms to the left:

157-(5+3x+2x^2)=0

We get rid of parentheses

-2x^2-3x-5+157=0

We add all the numbers together, and all the variables

-2x^2-3x+152=0

a = -2; b = -3; c = +152;
Δ = b2-4ac
Δ = -32-4·(-2)·152
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-35}{2*-2}=\frac{-32}{-4}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+35}{2*-2}=\frac{38}{-4}
=-9+1/2
$